template<class T, class U> constexpr bool operator==(const optional<T>& x, const U& v);
-1- Constraints: U is not a specialization of optional. The expression *x == v is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator==(const T& v, const optional<U>& x);
-3- Constraints: T is not a specialization of optional. The expression v == *x is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator!=(const optional<T>& x, const U& v);
-5- Constraints: U is not a specialization of optional. The expression *x != v is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator!=(const T& v, const optional<U>& x);
-7- Constraints: T is not a specialization of optional. The expression v != *x is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator<(const optional<T>& x, const U& v);
-9- Constraints: U is not a specialization of optional. The expression *x < v is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator<(const T& v, const optional<U>& x);
-11- Constraints: T is not a specialization of optional. The expression v < *x is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator>(const optional<T>& x, const U& v);
-13- Constraints: U is not a specialization of optional. The expression *x > v is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator>(const T& v, const optional<U>& x);
-15- Constraints: T is not a specialization of optional. The expression v > *x is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator<=(const optional<T>& x, const U& v);
-17- Constraints: U is not a specialization of optional. The expression *x <= v is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator<=(const T& v, const optional<U>& x);
-19- Constraints: T is not a specialization of optional. The expression v <= *x is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator>=(const optional<T>& x, const U& v);
-21- Constraints: U is not a specialization of optional. The expression *x >= v is well-formed and its result is convertible to bool.
template<class T, class U> constexpr bool operator>=(const T& v, const optional<U>& x);
-23- Constraints: T is not a specialization of optional. The expression v >= *x is well-formed and its result is convertible to bool.
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