class template
<type_traits>
std::decaytemplate <class T> struct decay;
Decay type
Obtains the decay type of T.The transformed type is aliased as member type decay::type.
The decay type of T is the same type that results from the standard conversions that happen when an lvalue expression is used as an rvalue, with its cv-qualifier stripped:
Notice that this class merely obtains a type using another type as model, but it does not transform values or objects between those types.
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// decay example
#include <iostream>
#include <type_traits>
typedef std::decay<int>::type A; // int
typedef std::decay<int&>::type B; // int
typedef std::decay<int&&>::type C; // int
typedef std::decay<const int&>::type D; // int
typedef std::decay<int[2]>::type E; // int*
typedef std::decay<int(int)>::type F; // int(*)(int)
typedef int X[3];
int main() {
std::cout << std::boolalpha;
std::cout << "typedefs of int:" << std::endl;
std::cout << "A: " << std::is_same<int,A>::value << std::endl;
std::cout << "B: " << std::is_same<int,B>::value << std::endl;
std::cout << "C: " << std::is_same<int,C>::value << std::endl;
std::cout << "D: " << std::is_same<int,D>::value << std::endl;
std::cout << "E: " << std::is_same<int,E>::value << std::endl;
std::cout << "F: " << std::is_same<int,F>::value << std::endl;
return 0;
}
typedefs of int: A: true B: true C: true D: true E: false F: false
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