function
<cstdlib>
atoiint atoi (const char * str);
Convert string to integer
Parses the C-string str interpreting its content as an integral number, which is returned as a value of typeint
.
The function first discards as many whitespace characters (as in isspace) as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minus sign followed by as many base-10 digits as possible, and interprets them as a numerical value.
The string can contain additional characters after those that form the integral number, which are ignored and have no effect on the behavior of this function.
If the first sequence of non-whitespace characters in str is not a valid integral number, or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed and zero is returned.
int
value.
int
, it causes undefined behavior. See strtol for a more robust cross-platform alternative when this is a possibility.
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/* atoi example */
#include <stdio.h> /* printf, fgets */
#include <stdlib.h> /* atoi */
int main ()
{
int i;
char buffer[256];
printf ("Enter a number: ");
fgets (buffer, 256, stdin);
i = atoi (buffer);
printf ("The value entered is %d. Its double is %d.\n",i,i*2);
return 0;
}
Enter a number: 73 The value entered is 73. Its double is 146.
If str does not point to a valid C-string, or if the converted value would be out of the range of values representable by an int
, it causes undefined behavior.
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