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Showing content from https://cplusplus.com/reference/cmath/modf/ below:

function

modf

double modf (double x, double* intpart);

     double modf  (double x     , double* intpart);      float modff (float x      , float* intpart);long double modfl (long double x, long double* intpart);

     double modf (double x     , double* intpart);      float modf (float x      , float* intpart);long double modf (long double x, long double* intpart);

     double modf (double x     , double* intpart);      float modf (float x      , float* intpart);long double modf (long double x, long double* intpart);     double modf (T x          , double* intpart);       // additional overloads

Break into fractional and integral parts

Breaks x into an integral and a fractional part.

The integer part is stored in the object pointed by intpart, and the fractional part is returned by the function.

Both parts have the same sign as x.

Additional overloads

are provided in this header (

<cmath>

) for the

integral types

: These overloads effectively cast

to a

double

before calculations (defined for

being any

integral type

Parameters

x: Floating point value to break into parts.
intpart: Pointer to an object (of the same type as x) where the integral part is stored with the same sign as x.

Return Value The fractional part of x, with the same sign.

Example

/* modf example */
#include <stdio.h>      /* printf */
#include <math.h>       /* modf */

int main ()
{
  double param, fractpart, intpart;

  param = 3.14159265;
  fractpart = modf (param , &intpart);
  printf ("%f = %f + %f \n", param, intpart, fractpart);
  return 0;
}

Output:

3.141593 = 3.000000 + 0.141593