A number of the figures above are in the shape of a trapezium. An a-b trapezium as shown below will contain ½b(2a+b-1) hexagons.
For the one-sided pentahexes the total area is 165 and so we must have b(2a+b-1)=330 from which we get the following possibilities for trapezia - 54-3; 31-5; 25-6; 12-10; 4-15 - all of which are shown above.
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