how about this, it work for the 3 requirements
def list_replace(origen,elem,new,cantidad=None):
n=0
resul=list()
len_elem=0
if isinstance(elem,list):
len_elem=len(elem)
for i,x in enumerate(origen):
if x==elem or elem==origen[i:i+len_elem]:
if cantidad and n<cantidad:
resul.extend(new)
n+=1
continue
elif not cantidad:
resul.extend(new)
continue
resul.append(x)
return resul
>>>list_replace([1,2,3,4,5,3,5,33,23,3],3,[42,42])
[1, 2, 42, 42, 4, 5, 42, 42, 5, 33, 23, 42, 42]
>>>list_replace([1,2,3,4,5,3,5,33,23,3],3,[42,42],2)
[1, 2, 42, 42, 4, 5, 42, 42, 5, 33, 23, 3]
>>>list_replace([1,2,3,4,5,3,5,33,23,3],[33,23],[42,42,42],2)
[1, 2, 3, 4, 5, 3, 5, 42, 42, 42, 23, 3]
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