Fredrik Lundh wrote:
> 5) check the number of links to each file
>
> n = os.stat(tempfile)[3]
> m = os.stat(lockfile)[3]
aw, forget that. I shouldn't trust google over my own code. here's the
correct algorithm:
f = open(tempfile, "w")
f.close()
n = os.stat(tempfile)[3]
os.link(tempfile, lockfile)
m = os.stat(tempfile)[3]
if n == m+1:
success!
where n==1 and m==2. the os.link call can be placed in a try/except
clause (if it fails, m won't be 2), or you can use a try/except around the
entire thing.
</F>
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