Bruno Desthuilliers wrote:
> 2/ functional solution:
> -----------------------
> def make_funcs():
> x = 0
> def _abc():
> x = 1
> return x + 1
> def _abcd():
> return x + 1
> return _abc, _abcd
>
> abc, abcd = make_funcs()
> print abc()
> print abcd()
The x in function _abc() is not the same as that in make_funcs() and _abcd()
as you can easily verify by modifying _abc() to
def _abc():
x # raises UnboundLocalError
x = 1
return x + 1
Once a variable is assigned a value the compiler treats it as local to that
function. Closed-over variables are therefore always read-only, much to the
chagrin of Lisp-lovers.
Peter
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