Let's say I define a list of pairs as follows: >>l = [('d', 3), ('a', 2), ('b', 1)] Can anyone explain why this does not work? >>h = {}.update(l) and instead I have to go: >>h = {} >>h.update(l) to initialize a dictionary with the given list of pairs? when an analagous operation on strings works fine: >>s = "".join(["d","o","g"]) Seems inconsistent. thanks, Scott
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