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Fri Apr 27 04:38:28 EDT 2001 · http://mail.python.org/pipermail/python-list/2001-April/103300.html

Bjorn Pettersen <BPettersen at NAREX.com> wrote in
<mailman.988332640.18020.python-list at python.org>: 

> Lambda only takes an expression and print is a statement (which is why
> you're getting a syntax error). If you really want to do this (and I'm
> not condoning it) you can do:
> 
>      import sys
>      map(lambda x: sys.stdout.write(x), ['line one', 'line two'])

or get rid of the lambda entirely:
    map(sys.stdout.write, ['line one', 'line two'])
except that neither of these options puts a newline between the elements of 
the list. This does though:
    list = ['line one', 'line two']
    [ sys.stdout.write(x+'\n') for x in list]

> 
> or
> 
>      def write(x):
>         print x
> 
>      map(lambda x: write(x), ['line one', 'line two'])

    	map(write, ['line one', 'line two'])

> 
> however,
> 
>      for x in ['line one', 'line two']:
>         print x
> 
> is much clearer IMHO.
Agreed.

[bottom quote snipped - please don't bottom quote your messages]

-- 
Duncan Booth                                             duncan at rcp.co.uk
int month(char *p){return(124864/((p[0]+p[1]-p[2]&0x1f)+1)%12)["\5\x8\3"
"\6\7\xb\1\x9\xa\2\0\4"];} // Who said my code was obscure?

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using lambda to print everything in a list