"Maurice Bauhahn" <bauhahnm at clara.net> wrote in message news:mailman.988158281.19384.python-list at python.org... > Thank you very much for your persistent help. > > I was able to get the 8th bit characters to act as keys...with a somewhat > complex construction: chr(int(linesplit[0])). Linesplit had decimal > numbers in text format. > Would this shed any light on your original question or help in solving your problem more compactly? Note that this is CPython, not Jython, but portability should make all this work in both implementations. From what I've read, it seems to be your need to see decimal numbers in the source whcih led you to these contortions. Your original assertion that """ >>> chr(127) '?' (in fact a character like a house) """ is quite correct, but I don't see why a weird printable representation makes a character unsuitable for use as a dictionary key. Maybe I missed your point. Anyway ... >>> # Construct a string of all chars from 0 to 255 >>> chars = "".join(map(chr, [i for i in range(256)])) >>> # Use decimal value to access single characters >>> # and use them as dictionary keys >>> dict = {} >>> dict[chars[233]] = "Two hundred thirty-three" >>> dict[chars[27]] = "escape" >>> dict["\033"] 'escape' >>> dict["\351"] 'Two hundred thirty-three' >>> dict {'\033': 'escape', '\351': 'Two hundred thirty-three'} >>> In other words, having constructed the chars[] list, you can index it with decimal numbers to get the characters you want. chars could equally have been a list of single-character strings, with the same effect. If this doesn't help you at all, please feel free to ignore my rantings. regards Steve > linesplit = split('\t',encodingline) > if (len(linesplit) > 5): > try: > templist = linesplit[2:4] > templist.append(split(';|:',linesplit[4])) > templist.append(strip(linesplit[5])) > encodedict[chr(int(linesplit[0]))] = templist > print templist > except ValueError: > logerror('My error', linesplit[0]) > else: > logerror('Not >5 fields long', linesplit) >
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