With the help of good folks on this list, the following Python program
has been created to help a newbie choose between and amongst 11
languages, namely Java, Visual Basic, C++, C, Lisp, Delphi (Pascal),
JavaScript, Python, Perl, Ruby, and Tcl...
Now, I keep coming up with Python, given my preferences, but your
mileage may vary...
Problems I still have
1. This program works fine for me when I run it under pythonWin, but
when I try to run it under IDLE, I get an error message after first
prompt, "Tcl error, expected boolean got ???' Why would a program run
fine under pythonwin but not under IDLE (on Win(98))
2. It's hard to make a program look nice, input and output wise, when
the inputs and outputs are so different under pythonwin vs IDLE, vs at
the Python DOS shell prompt...makes me want to run under Tkinter but I
still have not been able to figure that out..but there should be an
acceptable way to run under command line under all IDE's??
Here is the program called ProgramLanguageFinal.py:::(its still bit of
spaghetti code even though I used good code form this list' members but
I probably butchered it...
(with huge apologies to Jeff Epler)...
print "This is a program to help give you an idea which programming
languages you should consider learning."
print "While there are any number of languages you might consider, this
program considers only 11 of the most"
print "popular ones. The program will ask you to input a ranking or
weighting for a number of criteria"
print "that may be of importance in choosing your next programming
language."
def get_list(heading, prompt):
""" get_list(heading, prompt) -> list
This function prompts for a list of things. The heading is printed on
a line by itself, and the prompt must have a %d substitution for the
number of the item within the list.
"""
print heading
print
print "(enter a blank line to end the list)"
ret = []
i = 1
while 1:
line = raw_input(prompt % i)
if not line:
break
ret.append(line)
i=i+1
print
return ret
def get_number(prompt):
""" get_number(prompt) -> float
This function prompts for a number. If the user enters bad input, such
as
"cat" or "3l", it will prompt again.
"""
res = None
while res is None:
try:
res = float(raw_input(prompt))
except ValueError: pass
return res
options = ["Python", "Perl", "Ruby", "Tcl", "JavaScript", "Visual
Basic", "Java", "C++", "C", "Lisp", "Delphi"]
criteria = ["ease of learning", "ease of use", "speed of program
execution", "quality of available tools", "popularity", "power &
expressiveness", "cross platform?", "cost"]
rankings = {}
print
print "Enter relative importance of criteria (higher is more important)"
print
for c in criteria:
rankings[c] = get_number("Criterion %s: " % c)
# Next, get the user to score each option on all the criteria.
# Here, we index the dictionary on the pair (option, criterion).
# This is similar to a two-dimensional array in other languages
score = {("Python", "ease of learning"):100, ("Python", "ease of
use"):100, ("Python", "speed of program execution"):10, ("Python",
"quality of available tools"):70, ("Python", "popularity"):50,
("Python", "power & expressiveness"):100, ("Python", "cross
platform?"):100, ("Python", "cost"):100,
("Perl", "ease of learning"):50, ("Perl", "ease of use"):90, ("Perl",
"speed of program execution"):30, ("Perl", "quality of available
tools"):50, ("Perl", "popularity"):75, ("Perl", "power &
expressiveness"):100, ("Perl", "cross platform?"):100, ("Perl",
"cost"):100,
("Ruby", "ease of learning"):50, ("Ruby", "ease of use"):100, ("Ruby",
"speed of program execution"):20, ("Ruby", "quality of available
tools"):20, ("Ruby", "popularity"):10, ("Ruby", "power &
expressiveness"):100, ("Ruby", "cross platform?"):80, ("Ruby",
"cost"):100,
("Tcl", "ease of learning"):100, ("Tcl", "ease of use"):100, ("Tcl",
"speed of program execution"):10, ("Tcl", "quality of available
tools"):50, ("Tcl", "popularity"):40, ("Tcl", "power &
expressiveness"):10, ("Tcl", "cross platform?"):100, ("Tcl",
"cost"):100,
("JavaScript", "ease of learning"):70, ("JavaScript", "ease of use"):75,
("JavaScript", "speed of program execution"):10, ("JavaScript", "quality
of available tools"):50, ("JavaScript", "popularity"):100,
("JavaScript", "power & expressiveness"):40, ("JavaScript", "cross
platform?"):50, ("JavaScript", "cost"):100,
("Visual Basic", "ease of learning"):50, ("Visual Basic", "ease of
use"):100, ("Visual Basic", "speed of program execution"):20, ("Visual
Basic", "quality of available tools"):100, ("Visual Basic",
"popularity"):100, ("Visual Basic", "power & expressiveness"):50,
("Visual Basic", "cross platform?"):1, ("Visual Basic", "cost"):1,
("Java", "ease of learning"):15, ("Java", "ease of use"):50, ("Java",
"speed of program execution"):50, ("Java", "quality of available
tools"):100, ("Java", "popularity"):100, ("Java", "power &
expressiveness"):100, ("Java", "cross platform?"):100, ("Java",
"cost"):100,
("C++", "ease of learning"):10, ("C++", "ease of use"):25, ("C++",
"speed of program execution"):90, ("C++", "quality of available
tools"):100, ("C++", "popularity"):100, ("C++", "power &
expressiveness"):100, ("C++", "cross platform?"):100, ("C++",
"cost"):100,
("C", "ease of learning"):15, ("C", "ease of use"):10, ("C", "speed of
program execution"):100, ("C", "quality of available tools"):100, ("C",
"popularity"):100, ("C", "power & expressiveness"):100, ("C", "cross
platform?"):110, ("C", "cost"):100,
("Lisp", "ease of learning"):20, ("Lisp", "ease of use"):30, ("Lisp",
"speed of program execution"):70, ("Lisp", "quality of available
tools"):50, ("Lisp", "popularity"):25, ("Lisp", "power &
expressiveness"):110, ("Lisp", "cross platform?"):80, ("Lisp",
"cost"):90,
("Delphi", "ease of learning"):50, ("Delphi", "ease of use"):110,
("Delphi", "speed of program execution"):85, ("Delphi", "quality of
available tools"):100, ("Delphi", "popularity"):30, ("Delphi", "power &
expressiveness"):100, ("Delphi", "cross platform?"):80, ("Delphi",
"cost"):10}
# Calculate the resulting score for each option.
# The "result" dictionary is indexed with the names of the options.
result = {}
for o in options:
value = 0
for c in criteria:
value = value + rankings[c] * score[o, c]
result[o] = value
# Now, I want to take the dictionary result, and turn it into a ranked
list
results = result.items() # A list of tuples (key, value)
results.sort(lambda x, y: -cmp(x[1], y[1]))
# Sort the list using the reverse of the
# "value" of the entry, so that higher
# values come first
print
print "Results, in order from highest to lowest score"
print
print "%5s %s" % ("Score", "Option")
# Take the pairs out of results in order, and print them out
for option, result in results:
print "%5s %s" % (result, option)
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