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Mon Apr 23 15:38:08 EDT 2001 · http://mail.python.org/pipermail/python-list/2001-April/069356.html

If you declare aaa in the class body it will be a class varaible instead of
an instance variable which means that it's shared by all instances of this
class. If you want each myclass to have it's own aaa you must declare a
constructor that initializes this special instance like this:

class myclass:
    def __init__ (self, dict = None): # by looking at your code I presume
that you want to initialize your class with a dictionary
        if dict is None: dict = {}
        self.aaa=dict
    def add(self,u):
        (self.aaa)[u]=1
    def show(self):
        print self.aaa

HTH,
Nils

"Jacek Pliszka" <pliszka at fuw.edu.pl> schrieb im Newsbeitrag
news:Pine.LNX.4.30.0104232122310.23315-100000 at ift4.fuw.edu.pl...
> Hi!
>
> I just started to learn Python and I got stuck with the following
> problem:
>
> class myclass:
>     aaa={}
>     def add(self,u):
>         (self.aaa)[u]=1
>     def show(self):
>         print self.aaa
>
> ula=myclass({})
>
> ula.add(13)
>
> ola=myclass({})
>
> ula.add(11)
>
> ola.add(11)
>
> ula.show()
>
> ola.show()
>
> then I get the result that aaa in both ula and ola
> is identical!!! I thought that aaa will be different for
> ula and ola!!
>
> What am I doing wrong?
>
> Thanks in advance for any help,
>
> Jacek
>
>

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Newbie question about dictionaries in classes