Xin, Peixing wrote: > On certain platform, expm1() is implemented as exp() minus 1. To calculate > expm1(-1420.0), that will call exp(-1420.0) then substract 1. You know, > exp(-1420.0) will underflow to zero and errno is set to ERANGE. As a > consequence the errno keeps set there when expm1() returns the correct result > -1. This sounds like a bug in that platform's implementation of expm1() to me. Which platform is it? -- Greg
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