I was looking for a way to set a function being equal to another function: q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer); I was hoping to use something like this: (q).__setcall__.(m+1) = (q).__setcall__.(m)+ ((-1)^m) * exp(lnanswer); As a work around. But I have not found the `__setcall__' built in being there. Here is the code block I'm working with: indvar = 200; q = 0; lnanswer = 0; for m = 1:150 lnanswer = (3 * m) * log(indvar) - log(factorial(3 * m)) ; q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer); end lnanswer q Any help would be appreciated. Thank you -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://mail.python.org/pipermail/python-dev/attachments/20101024/3f1e8d62/attachment.html>
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