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[Python-Dev] operator precedence of __eq__, __ne__, etc, if both object have implementations

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Willem Broekema wrote:

> The AND above (which I uppercased) is subtle but important. In the "x
> op y" case with y being of a subclass of the class of x, if there is
> no class in between x and y (excluding x, including y) that overrides
> the __rop__ method, then y,__rop__(x) is *not* tried before
> x.__op__(y).

How does this work at the C typeslot level, where
there are no __rop__ methods?

-- 
Greg

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