Steven D'Aprano wrote: > it should be obvious in the > same way that string concatenation is different from numerical > addition: > > 1 + 2 = 2 + 1 > '1' + '2' != '2' + '1' However, the proposed arithmetic isn't just non- commutative, it's non-associative, which is a much rarer and more surprising thing. We do at least have ('1' + '2') + '3' == '1' + ('2' + '3') -- Greg
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