Jean-Paul Calderone schrieb: >> I'm uncertain whether D1.update(D2) will invoke callbacks (it >> probably will). > > Quite so: > > >>> class X: > ... def __del__(self): > ... print 'X.__del__' > ... > >>> a = {1: X()} > >>> b = {1: 2} > >>> a.update(b) > X.__del__ > >>> Ah, right: that's true for any assignment, then. Regards, Martin
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