On Fri, Mar 19, 2004 at 03:33:41PM -0500, Andrew Koenig wrote: > It certainly doesn't *require* a builtin operator. I do think, > however, that the proposed comparison is more useful than "is" in > most contexts in which programmers use "is" today. Are you saying that most instances of "is" in current Python code are incorrect? If not, what do you mean by more useful? Neil
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