On 03 May 2001, Paul F. Dubois said:
> 1. The simple case, X inherits from Y and in defining foo and bar needs to
> use Y's version:
>
> class X (Y rename foo as _sfoo,
> bar as _sbar
> ):
Maybe I'm being thick, but don't you get the same effect by doing this:
class X (Y):
_sfoo = Y.foo
_sbar = Y.bar
...or would the "rename" syntax also hide the "foo" and "bar" names from
X's effective namespace[1]? In that case, I guess some special syntax
is needed.
[1] "effective namespace" -- the union of X's class dict with all its
superclass' dicts; not actually X's namespace, but the set of names you
can use in X. I think. Err, whatever.
Greg
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