Paul> Actually, when I tried, I got into a bit of a mess getting the
Paul> type checks (which you need) right -
Paul> def olddiv(n,m):
Paul> if type(n) == type(m) == type(0):
Paul> return n//m
Paul> else:
Paul> return n/m
Paul> But this needs the checks expanded to take longs into
Paul> account. Which is where it gets messy.
Wouldn't this work for ints and longs?
def olddiv(n,m):
ints = [type(0), type(0L)]
if type(n) in ints and type(m) in ints:
return n//m
else:
return n/m
--
Skip Montanaro (skip@pobox.com)
http://www.mojam.com/
http://www.musi-cal.com/
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