Skip:
> Alternatively, how about os.path.suffixes? It would work similar to
> os.path.commonprefix, but instead of returning the prefix of a group of
> files, return a list of the suffixes resulting in the application of the
> common prefix:
To avoid duplication of effort, how about a single function
that does both:
>>> files = ["/home/swen", "/home/swanson", "/home/jules"]
>>> os.path.factorize(files)
("/home", ["swen", "swanson", "jules"])
Greg Ewing, Computer Science Dept, +--------------------------------------+
University of Canterbury, | A citizen of NewZealandCorp, a |
Christchurch, New Zealand | wholly-owned subsidiary of USA Inc. |
greg@cosc.canterbury.ac.nz +--------------------------------------+
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