On Thu, 3 Aug 2000, Tim Peters wrote: > > >>> "\x123465" # \x12 -> \022, "3456" left alone > '\0223456' > >>> "\x65" > 'e' > >>> "\x1" > ValueError > >>> "\x\x" > ValueError > >>> I'm quite certain that this should be a SyntaxError, not a ValueError: >>> "\x1" SyntaxError: two hex digits are required after \x >>> "\x\x" SyntaxError: two hex digits are required after \x Otherwise, +1. Sounds great. -- ?!ng
RetroSearch is an open source project built by @garambo | Open a GitHub Issue
Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo
HTML:
3.2
| Encoding:
UTF-8
| Version:
0.7.4