> How do endian issues fit in with \u?
I would assume that it uses the same rules as hex and octal numeric
literals: these are always *written* in big-endian notation, since
that is also what we use for decimal numbers. Thus, on a
little-endian machine, the short integer 0x1234 would be stored as the
bytes {0x34, 0x12} and so would the string literal "\x1234".
--Guido van Rossum (home page: http://www.python.org/~guido/)
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