Bugs item #495094, was opened at 2001-12-19 08:44
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Category: Python Interpreter Core
Group: Python 2.1.1
>Status: Deleted
Resolution: None
Priority: 5
Submitted By: Fahri Basegmez (basegmez)
Assigned to: Tim Peters (tim_one)
Summary: evaluating integers inconsistently
Initial Comment:
Python 2.1.1 (#20, Jul 20 2001, 01:19:29) [MSC 32 bit
(Intel)] on win32
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information.
IDLE 0.8 -- press F1 for help
>>> eval('01234')
668
>>> for i in range(10):print eval('0' + str(i))
0
1
2
3
4
5
6
7
Traceback (most recent call last):
File "<pyshell#2>", line 1, in ?
for i in range(10):print eval('0' + str(i))
File "<string>", line 1
08
^
SyntaxError: unexpected EOF while parsing
>>> 08
SyntaxError: invalid syntax
>>> 01
1
>>> 0123456
42798
>>> 0123456L
42798L
>>>
eval function and Python interpreter evaluates
integers/long integers inconsistenly. It should be an
error either for all cases or for none.
Fahri Basegmez
----------------------------------------------------------------------
Comment By: Tim Peters (tim_one)
Date: 2001-12-19 10:57
Message:
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user_id=31435
Hmm. What is your complaint here, exactly? You showed a
bunch of code but didn't point out anything that surprised
me. Do you know that integer literals beginning with "0"
are in octal notation (so that the digits '8' and '9'
aren't legal then, and 010 is decimal 8?). Similarly,
integer literals beginning with "0x" are in hex notation.
A decimal integer literal cannot begin with 0.
----------------------------------------------------------------------
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