float expf( float arg );
(1) (since C99)double exp( double arg );
(2)long double expl( long double arg );
(3) (since C99)#define exp( arg )
(4) (since C99) 1-3)Computes
e(
Euler's number,
2.7182818...) raised to the given power
arg.
4)Type-generic macro: If
arghas type
long double,
expl
is called. Otherwise, if
arghas integer type or the type
double,
exp
is called. Otherwise,
expf
is called. If
argis complex or imaginary, then the macro invokes the corresponding complex function (
cexpf,
cexp,
cexpl).
[edit] Parameters arg - floating-point value [edit] Return valueIf no errors occur, the base-e exponential of arg (earg
) is returned.
If a range error occurs due to overflow, +HUGE_VAL, +HUGE_VALF, or +HUGE_VALL is returned.
If a range error occurs due to underflow, the correct result (after rounding) is returned.
[edit] Error handlingErrors are reported as specified in math_errhandling.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
For IEEE-compatible type double, overflow is guaranteed if 709.8 < arg, and underflow is guaranteed if arg < -708.4.
[edit] Example#include <errno.h>
#include <fenv.h>
#include <float.h>
#include <math.h>
#include <stdio.h>
// #pragma STDC FENV_ACCESS ON
int main(void)
{
printf("exp(1) = %f\n", exp(1));
printf("FV of $100, continuously compounded at 3%% for 1 year = %f\n",
100*exp(0.03));
// special values
printf("exp(-0) = %f\n", exp(-0.0));
printf("exp(-Inf) = %f\n", exp(-INFINITY));
//error handling
errno = 0; feclearexcept(FE_ALL_EXCEPT);
printf("exp(710) = %f\n", exp(710));
if (errno == ERANGE)
perror(" errno == ERANGE");
if (fetestexcept(FE_OVERFLOW))
puts(" FE_OVERFLOW raised");
}
Possible output:
exp(1) = 2.718282
FV of $100, continuously compounded at 3% for 1 year = 103.045453
exp(-0) = 1.000000
exp(-Inf) = 0.000000
exp(710) = inf
errno == ERANGE: Numerical result out of range
FE_OVERFLOW raised[edit] References
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