Compute the truth value of x1 XOR x2, element-wise.
>>> np.logical_xor(True, False) True >>> np.logical_xor([True, True, False, False], [True, False, True, False]) array([False, True, True, False], dtype=bool)
>>> x = np.arange(5) >>> np.logical_xor(x < 1, x > 3) array([ True, False, False, False, True], dtype=bool)
>>> np.logical_xor(0, np.eye(2))
array([[ True, False],
[False, True]], dtype=bool)
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