Baseline 2023
Newly available
The toSpliced()
method of Array
instances is the copying version of the splice()
method. It returns a new array with some elements removed and/or replaced at a given index.
toSpliced(start)
toSpliced(start, skipCount)
toSpliced(start, skipCount, item1)
toSpliced(start, skipCount, item1, item2)
toSpliced(start, skipCount, item1, item2, /* â¦, */ itemN)
Parameters
start
Zero-based index at which to start changing the array, converted to an integer.
-array.length <= start < 0
, start + array.length
is used.start < -array.length
or start
is omitted, 0
is used.start >= array.length
, no element will be deleted, but the method will behave as an adding function, adding as many elements as provided.skipCount
Optional
An integer indicating the number of elements in the array to remove (or, to skip) from start
.
If skipCount
is omitted, or if its value is greater than or equal to the number of elements after the position specified by start
, then all the elements from start
to the end of the array will be deleted. However, if you wish to pass any itemN
parameter, you should pass Infinity
as skipCount
to delete all elements after start
, because an explicit undefined
gets converted to 0
.
If skipCount
is 0
or negative, no elements are removed. In this case, you should specify at least one new element (see below).
item1
, â¦, itemN
Optional
The elements to add to the array, beginning from start
.
If you do not specify any elements, toSpliced()
will only remove elements from the array.
A new array that consists of all elements before start
, item1
, item2
, â¦, itemN
, and all elements after start + skipCount
.
The toSpliced()
method, like splice()
, does multiple things at once: it removes the given number of elements from the array, starting at a given index, and then inserts the given elements at the same index. However, it returns a new array instead of modifying the original array. The deleted elements therefore are not returned from this method, but they remain accessible in the original array.
The toSpliced()
method never produces a sparse array. If the source array is sparse, the empty slots will be replaced with undefined
in the new array.
The toSpliced()
method is generic. It only expects the this
value to have a length
property and integer-keyed properties.
You can use toSpliced()
to delete, add, and replace elements in an array and create a new array more efficiently than using slice()
and concat()
.
const months = ["Jan", "Mar", "Apr", "May"];
// Inserting an element at index 1
const months2 = months.toSpliced(1, 0, "Feb");
console.log(months2); // ["Jan", "Feb", "Mar", "Apr", "May"]
// Deleting two elements starting from index 2
const months3 = months2.toSpliced(2, 2);
console.log(months3); // ["Jan", "Feb", "May"]
// Replacing one element at index 1 with two new elements
const months4 = months3.toSpliced(1, 1, "Feb", "Mar");
console.log(months4); // ["Jan", "Feb", "Mar", "May"]
// Original array is not modified
console.log(months); // ["Jan", "Mar", "Apr", "May"]
Using toSpliced() on sparse arrays
The toSpliced()
method always creates a dense array.
const arr = [1, , 3, 4, , 6];
console.log(arr.toSpliced(1, 2)); // [1, 4, undefined, 6]
Calling toSpliced() on non-array objects
The toSpliced()
method reads the length
property of this
. It then reads the integer-keyed properties needed and writes them into the new array.
const arrayLike = {
length: 3,
unrelated: "foo",
0: 5,
2: 4,
};
console.log(Array.prototype.toSpliced.call(arrayLike, 0, 1, 2, 3));
// [2, 3, undefined, 4]
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